(3b^2+2b-4)/(b-2)

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Solution for (3b^2+2b-4)/(b-2) equation: 


D( b )

b-2 = 0

b-2 = 0

b-2 = 0

b-2 = 0 // + 2

b = 2

b in (-oo:2) U (2:+oo)

(3*b^2+2*b-4)/(b-2) = 0

3*b^2+2*b-4 = 0

3*b^2+2*b-4 = 0

DELTA = 2^2-(-4*3*4)

DELTA = 52

DELTA > 0

b = (52^(1/2)-2)/(2*3) or b = (-52^(1/2)-2)/(2*3)

b = (2*13^(1/2)-2)/6 or b = (-2*13^(1/2)-2)/6

(b-((-2*13^(1/2)-2)/6))*(b-((2*13^(1/2)-2)/6)) = 0

((b-((-2*13^(1/2)-2)/6))*(b-((2*13^(1/2)-2)/6)))/(b-2) = 0

( b-((-2*13^(1/2)-2)/6) )

b-((-2*13^(1/2)-2)/6) = 0 // + (-2*13^(1/2)-2)/6

b = (-2*13^(1/2)-2)/6

( b-((2*13^(1/2)-2)/6) )

b-((2*13^(1/2)-2)/6) = 0 // + (2*13^(1/2)-2)/6

b = (2*13^(1/2)-2)/6

b in { (-2*13^(1/2)-2)/6, (2*13^(1/2)-2)/6 }

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